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Home/ Questions/Q 9273679
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T16:10:16+00:00 2026-06-18T16:10:16+00:00

There seems to be some stripping issue with jQuery when retrieving integer values from

  • 0

There seems to be some stripping issue with jQuery when retrieving integer values from input values.

My code:

    // Control the rating input field to only accept numeric values
    // -else set the values back to 0
    // For the highest value:
    $('.dsListItem .firstItem').keyup(function(){
        if (isNumber($(this).val()) && $(this).val() < $('.dsListItem .lastItem').val()) {
            console.log('FIRST: ' + $(this).val() + ' >>> ' + $('.dsListItem .lastItem').val());
            $(this).val($('.dsListItem .lastItem').val());
        }
    });
    // For the lowest value:
    $('.dsListItem .lastItem').keyup(function(){
        if (isNumber($(this).val()) && $(this).val() > $('.dsListItem .firstItem').val()) {
            console.log('LAST: ' + $(this).val() + ' >>> ' + $('.dsListItem .firstItem').val());
            $(this).val($('.dsListItem .firstItem').val());
        }
    });

Safari Inspector tells me this:

LAST: 11 >>> 10

LAST: 2 >>> 10

LAST: 1 >>> 10

Only 0 and 1 are valid. If 10 is validated as “1”, it should not pass 1 > 1 either, but yet it does.

I don’t get it why the console.log() print shows the correct integers but when I calculate with it the 10 get’s converted into a 1.

I tried casting the number with ($(this).val() * 1), yet that didn’t change anything, and anyway; the value is already checked to be a valid numeric value.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T16:10:17+00:00Added an answer on June 18, 2026 at 4:10 pm

    If you are sure that you are using numerical values then you have to cast them with a parseInt, so you’ll be sure that Javascript too will be talking with numbers, and not comparing numbers to strings!

    I think casting with parseInt is stronger than casting by a *1 instruction…

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