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Asked: 2026-06-14T03:11:57+00:00

There’s a byte[4] containing char codes for random hex numbers, i.e. b[0] == 49,

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There’s a byte[4] containing char codes for random hex numbers, i.e. b[0] == 49, b[1] == 68, b[2] == 70 …

I’d like to calculate something with these hex values, so I need to cast the char values to int. That sounds simple, but my solution looks terrible: 

char c1 = ((char)b[0]);
String s1 = String.valueOf(c1);
int p1 = Integer.parseInt(s1);

char c2 = ((char)b[1]);
String s2 = String.valueOf(c2);
int p2 = Integer.parseInt(s2);

...

Isn’t there a shorter method? There’s so many generic key words in my question that I can’t find a solution through google either.

Updated post:

Whoops, I forgot to mention the byte[] contains hex values. So

int x = b[0] - '0';

won’t suffice.

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1 Answer

  1. Editorial Team

    How about:

    int p1 = b[0];
// etc

    Oh, wait. You want to interpret the characters as digits and use the values. If you’re sure that the byte values are ASCII digit codes, you can do this:

    int p1 = b[0] - '0';
// etc

    If you want a formally correct way to do it:

    int p1 = Character.getNumericValue(b[0]);
// etc

    This will correctly handle hex characters (0, 1, …, F) and even things like '\u216C' (ROMAN NUMERAL FIFTY).

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