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Home/ Questions/Q 9259539
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T12:40:55+00:00 2026-06-18T12:40:55+00:00

This class is for managing a database through mysqli. I’m stuck on the prepared

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This class is for managing a database through mysqli. I’m stuck on the prepared statement to show all the column names of a given table.

class databaseManager {
    function showTable ($tableName, $mysqli) {
        $stmt = $mysqli -> prepare("SHOW COLUMNS FROM ?");
        $stmt -> bind_param('s', $tableName);
        $stmt -> execute();

        while ($stmt -> fetch) {
            $Field;
        }

        $stmt -> free_result();
    }
}

I get the error “Call to a member function bind_param() on a non-object”, but $mysqli connection exists so I suppose the mysqli -> prepare is wrong.

EDIT: clearly I passed $mysqli

$databaseManager = new databaseManager();
$databaseManager -> showTable("blog", $mysqli);
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  1. Editorial Team
    Editorial Team
    2026-06-18T12:40:56+00:00Added an answer on June 18, 2026 at 12:40 pm

    First, you aren’t doing any error handling.
    Always check results of all database interactions.

    For example,

    $stmt = $mysqli->prepare("SHOW COLUMNS FROM ?");
    if (!$stmt) {
        throw new Exception($mysqli->error);
    }
    

    so, you will get an error message from database.

    Next, you can’t bind identifier via prepared statement.
    So, you have to either whitelist it of format it properly, according to documentation

    By the way, I see not much point in such a function. I am using console for this purpose and other people usually see their database structure via PHPMyAdmin

    Also, using bare API is not the best choice. By using some abstraction layer you can make your code in one line:

    function showTable ($tableName) {
        return $this->db->getCol("SHOW COLUMNS FROM ?n", $tableName);
    }
    

    You don’t need this query to show table contents though, as column names always already present in a resultset. So, just request your data first and then extract column names from it

    by using such a library mentioned above, it would be like this

    $data  = $this->db->getAll("SELECT * FROM ?n", $tableName);
    $names = array_keys($data[0]);
    

    But still PHPMyAdmin is WAY better at it, give it a try

    If you need some sort of online table editor, it is seldom works such straight way. There are always some issues which require pre- or post-processing of data. And for whatever complex data structure you always end up with dedicated code. To show nice column titles for example.
    But for a few plain string values it would work.

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