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Home/ Questions/Q 7540949
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T07:46:03+00:00 2026-05-30T07:46:03+00:00

This doesn’t work: $string = ‘Hello world’; if(strpos($string, ‘\n’)) { echo ‘New line break

  • 0

This doesn’t work:

$string = 'Hello
    world';

if(strpos($string, '\n')) {
    echo 'New line break found';
}
else {
    echo 'not found';
}

Obviously because the string doesn’t have the “\n” character in it. But how else can I check to see if there is a line break that is the result of the user pressing enter in a form field?

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  1. Editorial Team
    Editorial Team
    2026-05-30T07:46:05+00:00Added an answer on May 30, 2026 at 7:46 am

    Your existing test doesn’t work because you don’t use double-quotes around your line break character ('\n'). Change it to:

    if(strstr($string, "\n")) {

    Or, if you want cross-operating system compatibility:

    if(strstr($string, PHP_EOL)) {

    Also note that strpos will return 0 and your statement will evaluate to FALSE if the first character is \n, so strstr is a better choice. Alternatively you could change the strpos usage to:

    if(strpos($string, "\n") !== FALSE) {
      echo 'New line break found';
    }
    else {
      echo 'not found';
    }
    
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