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Home/ Questions/Q 6001899
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T00:54:02+00:00 2026-05-23T00:54:02+00:00

This is a simple question I know, I’ve looked on google but can’t find

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This is a simple question I know, I’ve looked on google but can’t find much help. I’m trying to create an object, with my own custom parameters, and then call one of them in an alert.

Whatever I try, doesn’t seem to work, I know this is pretty simple stuff and I appologise! All my other JS in my time have been pretty simple and all inline because of that, I’m moving on to more OOP JS now.

$.fn.DataBar = function() {

        $.DataBar.defaultOptions = {
            class: 'DataBar',
            text: 'Enter Text Here'
        }

        this.greet = function() {
            alert(this.text);
        };
} 

var q = new $.DataBar();
q.greet();
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  1. Editorial Team
    Editorial Team
    2026-05-23T00:54:03+00:00Added an answer on May 23, 2026 at 12:54 am
    1. You don’t need the fn part, simply use:

      $.DataBar = function () { ... };
      

      $.fn is simply a reference to jQuery’s internal prototype. So $.fn.DataBar is intended to be used as $(selector).DataBar(), not $.DataBar().

    2. Your default options aren’t being applied to the newly created object. Optionally, you can also define the greet function on DataBar‘s prototype:

      $.DataBar = function () {
          $.extend(this, $.DataBar.defaultOptions);
      };
      
      $.DataBar.prototype.greet = function () {
          alert(this.text);
      };
      
      $.DataBar.defaultOptions = {
          class: 'DataBar',
          text: 'Enter Text Here'
      };
      
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