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Home/ Questions/Q 582021
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:38:32+00:00 2026-05-13T14:38:32+00:00

This is from TTL: //////////////////////////////////////////////////////////// // run-time type switch template <typename L, int N

  • 0

This is from TTL:

////////////////////////////////////////////////////////////
//  run-time type switch
template <typename L, int N = 0, bool Stop=(N==length<L>::value) > struct type_switch;

template <typename L, int N, bool Stop>
  struct type_switch
  {
    template< typename F >
      void operator()( size_t i, F& f )
      {
        if( i == N )
        {
          f.operator()<typename impl::get<L,N>::type>();
        }
        else
        {
          type_switch<L, N+1> next;
          next(i, f);
        }
      }
  };

It’s used for typeswitching on a TypeList. Question is — they are doing this via a series of nested if’s. Is there a way to do this type switch as a single select statement instead?

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:38:32+00:00Added an answer on May 13, 2026 at 2:38 pm

    You’ll need the preprocessor to generate a big switch. You’ll need get<> to no-op out-of-bound lookups. Check the compiler output to be sure unused cases produce no output, if you care; adjust as necessary ;v) .

    Check out the Boost Preprocessor Library if you care to get good at this sort of thing…

    template <typename L>
      struct type_switch
      {
        template< typename F >
          void operator()( size_t i, F& f )
          {
            switch ( i ) {
             #define CASE_N( N ) \
             case (N): return f.operator()<typename impl::get<L,N>::type>();
             CASE_N(0)
             CASE_N(1)
             CASE_N(2)
             CASE_N(3) // ad nauseam.
          }
      };
    
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