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Home/ Questions/Q 6253017
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T13:54:48+00:00 2026-05-24T13:54:48+00:00

This is my code: var shuffle = function(x) { var deck = []; deck.push(x);

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This is my code:

var shuffle = function(x) {
    var deck = [];
    deck.push(x);

    return deck;
};

var Placemat = function() {
    var card1 = deck.shift();
    var card2 = deck.shift();
}

By returning deck in shuffle() like this, can I use it in Placemat()? If not, how can I do it?

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  1. Editorial Team
    Editorial Team
    2026-05-24T13:54:49+00:00Added an answer on May 24, 2026 at 1:54 pm

    Yes you could. But anytime you call .shuffle() you would overwrite that array, or more precisely, create a new instance. So if you want to keep that reference you could go like

    var shuffle = (function() {
        var deck = [];
    
        return function(x) {
            deck.push(x);
    
            return deck;
        };
    }());
    

    Now .shuffle() closes over the deck by returning another function. So it could look like

    var Placemat = function() {
        var myDeck = shuffle(5);
    
        shuffle(10);
        shuffle(15);
    
        var card1 = deck.shift();
        var card2 = deck.shift();
    }
    

    Even if that is probably not the greatest way to go. But I guess I don’t even know what exactly you want to achieve there.

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