Question

This is my first attempt at a JOIN MySQL statement…

I have 2 tables..games and games_ratings

both tables have an id column. the id represents the id of the game. and i only want to get the average of the ints in the rating column where the id in games_ratings is equal to the id from the games table.

SELECT a.id, a.name, AVG(b.rating) AS average FROM games a LEFT JOIN games_ratings b GROUP BY a.id ORDER BY average DESC LIMIT 50;

any ideas?

Answer 1

Try this:

SELECT a.id, a.name, AVG(b.rating) AS average 
    FROM games a 
    LEFT JOIN games_ratings b
    ON a.id = b.id # <-- You need this line I believe 
GROUP BY a.id
ORDER BY average DESC LIMIT 50;

Edit: This is a bit hard without your complete schema, but you can try something like this.

SELECT a.id, a.name, AVG(b.rating) AS average, COUNT( b.id) as votes
    FROM games a 
    LEFT JOIN games_ratings b
    ON a.id = b.id 
GROUP BY a.id
ORDER BY votes DESC, average DESC LIMIT 50; # <-- You may need to modify this line