Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6983197
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T18:23:14+00:00 2026-05-27T18:23:14+00:00

This is my setting: display_startup_errors = on display_errors = On error_reporting = E_ALL |

  • 0

This is my setting:
display_startup_errors = on
display_errors = On
error_reporting = E_ALL | E_STRICT

$b;
function func ($name) {
  global $b;
  $b = 10;
  return $b;
  }
$a =& func("myname");
++$a ;
echo '<br/>$a= '.$a.' $b= ' .$b."<br/>";
xdebug_debug_zval('a'); echo "<br/> ";

The above code output’s the following notice:

Strict standards: Only variables should be assigned by reference in /path/to/file/file.php on line ‘some line number’
$a= 11 $b= 10
a: (refcount=1, is_ref=0)=11

Why is the above code displaying the notice? And why is there a C.O.W (copy on write) taking place?

$b;
function &func ($name) {//change here: to return a reference.
  global $b;
  $b = 10;
  return $b;
  }
$a =& func("myname");
++$a ;
echo '<br/>$a= '.$a.' $b= ' .$b."<br/>";
xdebug_debug_zval('a'); echo "<br/> ";

The above code will output:

$a= 11 $b= 11
a: (refcount=1, is_ref=1)=11

Why is no strict standards notice thrown here? And here the reference works.

$b;
function &func ($name) {
  global $b;
  $b = 10;
  return $b;
  }
$a = func("myname"); //change here: removed &
++$a ;
echo '<br/>$a= '.$a.' $b= ' .$b."<br/>";
xdebug_debug_zval('a'); echo "<br/> ";

The above code will output:

$a= 11 $b= 10
a: (refcount=1, is_ref=0)=11

Why does a C.O.W take place here?

For info on xdebug_debug_zval visit here.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-27T18:23:15+00:00Added an answer on May 27, 2026 at 6:23 pm

    How the hell did I miss this: This completely mutes my question!
    from Returning References at PHP manual

    Note: If you try to return a reference from a function with the syntax: return ($this->value); this will not work as you are attempting to return the result of an expression, and not a variable, by reference. You can only return variables by reference from a function – nothing else. Since PHP 4.4.0 in the PHP 4 branch, and PHP 5.1.0 in the PHP 5 branch, an E_NOTICE error is issued if the code tries to return a dynamic expression or a result of the new operator.

    To use the returned reference, you must use reference assigment:

    <?php
    function &collector() {
      static $collection = array();
      return $collection;
    }
    $collection = &collector();
    $collection[] = 'foo';
    ?>
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

This is my setting: display_startup_errors = on display_errors = On error_reporting = E_ALL |
I had this setting in my php.ini file: error_reporting = E_ERROR|E_PARSE|E_CORE_ERROR|E_COMPILE_ERROR But I was
When I do this : // --------------- SETTING NAVIGATION BAR LEFT BUTTON activityIndicator =
Does setting this value have the same effect as setting the debug=true in the
Why is this code setting artistImage to an image with 0 width and 0
Ok I'm at my work this friday setting up a table that will have
If so why? I know setting this on will result in more number of
Is there a good tutorial or does anyone have experience with setting this up
I have DataTemplate containing a TextBox . I'm setting this template to a listbox
I have following this blog in setting Xvfb in my ubuntu environment: http://corpocrat.com/2008/08/19/how-to-install-xvfb-x11-server-in-linux-server/ So

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.