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Home/ Questions/Q 3316094
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T22:25:43+00:00 2026-05-17T22:25:43+00:00

This is my situation: i need the code to run in a loop, over

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This is my situation:

i need the code to run in a loop, over and over again asking the same question(s) to the user, until the user types a “q” for any point to terminate/exit the loop, thus exiting the program.

The problem is that i tried to used a do-while/while loop, and those loops executes only if the conditions comes out to be true. But i need the condition (“q”) to be false so it can continue the loop. If the condition is true (input.equals(“q”)) , then it just does not nothing because instead of the integer/double, it will use a string (“q”) to calculate the distance.

i have already figured out how to get the distance, the code as is works well, but is there any work-around that i can make the loop continue while the condition is false?

and by the way, i am just barely learning java just in case…

‘.

import java.*;
public class Points {
public static void main(String[] args){

    java.util.Scanner input = new java.util.Scanner(System.in);

    System.out.print("Enter the first X coordinate: ");
    double x1 = input.nextDouble();
    System.out.print("Enter the first Y coordinate: ");
    double y1 = input.nextDouble();
    System.out.print("Enter the second X coordinate: ");
    double x2 = input.nextDouble();
    System.out.print("Enter the second Y coordinate: ");
    double y2 = input.nextDouble();
    System.out.println("(" + x1 + ", " + y1  + ")" + " " + "(" + x2 + ", " + y2+ ")");

    double getSolution = Math.sqrt(((x2-x1) * (x2-x1)) + ((y2-y1) * (y2-y1)));
    System.out.println(getSolution);
    }
}'
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T22:25:44+00:00Added an answer on May 17, 2026 at 10:25 pm

    The solution to this is to use String line = input.nextLine() instead of nextDouble(). Then you can have a method like:

    public static boolean timeToExit(String input) {
        return input.equalsIgnoreCase("q");
    }
    

    This method will need to be called each time the user provides input:

    if (timeToExit(line)) break;
    

    That will exit a loop.

    Now, since you have a String representation of the double, you will need to use Double.parseDouble(line) to turn the String into a number.

    Then all you have to do is enclose everything in an infinite loop -> while(true) { }

    And, the only time it will exit the loop is if the timeToExit method returned true, and you break the loop.

    This all turns into something like:

    while (true) {
        ...
        System.out.print("Enter the first X coordinate: ");
        String x1 = input.nextLine();
        if (timeToExit(x1)) break;
        double x1_d = Double.parseDouble(x1);
        ...
    }
    
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