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Home/ Questions/Q 7635579
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T07:27:46+00:00 2026-05-31T07:27:46+00:00

This is really easy in some languages, not so easy in others. I can’t

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This is really easy in some languages, not so easy in others. I can’t quite get it for C++. I’m reading in a file with thousands of lines of the format in the question title, and reading the file over and over again thousands of times.

Basically, I have some integers in mind in my program, say “100, 4, 1“, and I want to look up in a text file what the last digit in the sequence is, so the line might be “100_4_1 - 15“, i want to get the 15. How can this be done?

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  1. Editorial Team
    Editorial Team
    2026-05-31T07:27:47+00:00Added an answer on May 31, 2026 at 7:27 am

    some integers in mind in my program, say “100, 4, 1”,
    “100_4_1 – 15”, i want to get the 15

    struct Key
    {
        int a_, b_, c_;
        Key(int a, int b, int c) : a_(a), b_(b), c_(c) { }
        bool operator<(const Key& rhs) const
        {
            return a_ < rhs.a_ ||
                   a_ == rhs.a_ && b_ < rhs.b_ ||
                   a_ == rhs.a_ && b_ == rhs.b_ && c_ < rhs.c_;
        }
    };
    
    typedef std::map<Key, int> Lookup_Table;
    Lookup lookup_table;
    
    if (std::ifstream if("filename.txt"))
    {
        int a, b, c;
        char ignore_char;
        int number;
        while (if >> a >> ignore_char >> b >> ignore_char >> c >> ignore_char >> number)
            lookup_table[Key(a, b, c)] = number;
    }
    else
    {
        std::cerr << "can't read input file...\n";
        exit(1);
    }
    
    // to find something:
    Lookup_Table::const_iterator i = lookup_table.find(Key(x, y, z));
    if (i != lookup_table.end())
    {
        // found... value accessible using *i...
    }
    
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