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Asked: May 10, 20262026-05-10T20:31:52+00:00 2026-05-10T20:31:52+00:00

(This is related to Floor a date in SQL server .) Does a deterministic

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(This is related to Floor a date in SQL server.)

Does a deterministic expression exist to floor a DATETIME? When I use this as a computed column formula:

DATEADD(dd, DATEDIFF(dd, 0, [datetime_column]), 0) 

the I get an error when I place an index on that column:

Cannot create index because the key column ‘EffectiveDate’ is non-deterministic or imprecise.

But both DATEDIFF and DATEADD are deterministic functions by definition. Where is the catch? Is it possible?

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  1. 2026-05-10T20:31:52+00:00Added an answer on May 10, 2026 at 8:31 pm

    My guess is that this is a bug of some sorts. In SQL 2005 I was able to create such an indexed view without a problem (code is below). When I tried to run it on SQL 2000 though I got the same error as you are getting.

    The following seems to work on SQL 2000, but I get a warning that the index will be ignored AND you would have to convert every time that you selected from the view.

    CONVERT(CHAR(8), datetime_column, 112) 

    Works in SQL 2005:

    CREATE TABLE dbo.Test_Determinism (     datetime_column DATETIME    NOT NULL    DEFAULT GETDATE()) GO  CREATE VIEW dbo.Test_Determinism_View WITH SCHEMABINDING AS     SELECT         DATEADD(dd, DATEDIFF(dd, 0, [datetime_column]), 0) AS EffectiveDate     FROM         dbo.Test_Determinism GO  CREATE UNIQUE CLUSTERED INDEX IDX_Test_Determinism_View ON dbo.Test_Determinism_View (EffectiveDate) GO 
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