Question

This is the snippet of code in Java:

int i = 1234567890;     
float f = i;    
System.out.println(i - (int)f);

Why is that the output is not equal to 0? It performs widening, so it is not supposed to loose data. Then you just truncate the value.
Best regards

Answer 1

See the difference

 int i = 1234567890;     
 float f = i;    
 System.out.println(i - f);
 System.out.println((int)f);
 System.out.println(f);
 System.out.println(i-(int)f);

Ouput:

0.0

1234567936

1.23456794E9

-46