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Home/ Questions/Q 8188411
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T02:54:10+00:00 2026-06-07T02:54:10+00:00

This is the working original code: // … unsigned __int64 num = 57; sprintf_s(buffer,

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This is the working original code:

// ...
unsigned __int64 num = 57;
sprintf_s(buffer, sizeof(buffer), "%llu", num);

However, when I try to extract this part into this function:

void addBuffered(void** attributeValue, char* format)
{
    sprintf_s(buffer, sizeof(buffer), format, *attributeValue);
}

by calling:

addBuffered((void**)&num, "%d");

I have to change the format parameter in sprintf_s from %llu to %d to get the correct value. Can somebody explain why this happens and if the change of the parameter to %d can be a problem? Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-07T02:54:12+00:00Added an answer on June 7, 2026 at 2:54 am

    This happens because sizeof(void *) == 4 in your case. And you implicitly cast __int64 to void * by function call. So if you use %llu format, you print some garbage from memory.

    I suggest you to rewrite function if it is possible:

    template <typename T>
    void addBuffered(T *attributeValue, char* format)
    {
        sprintf_s(buffer, sizeof(buffer), format, *attributeValue);
    }
    

    call example:

    addBuffered(&num, "%luu");
    
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