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Home/ Questions/Q 678735
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T01:10:57+00:00 2026-05-14T01:10:57+00:00

This is what I’m trying to do: def call_block(in_class = String, &block) instance =

  • 0

This is what I’m trying to do:

def call_block(in_class = "String", &block)
    instance = eval("#{in_class}.new")
    puts "instance class: #{instance.class}"
    instance.instance_eval{ block.call }
end


# --- TEST EXAMPLE ---
# This outputs "class: String" every time
"sdlkfj".instance_eval {  puts "class: #{self.class}" }

# This will only output "class: Object" every time
# I'm trying to get this to output "class: String" though
call_block("String") { puts "class: #{self.class}" }

On the line where it says “instance.instance_eval{ block.call }”, I’m trying to find another way to make the new instance variable run instance eval on the block. The only way I can think of to get it to do that is to pass instance_eval the original block, not as a variable or anything, but as a real block like in the test example.

Any tips?

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  1. Editorial Team
    Editorial Team
    2026-05-14T01:10:57+00:00Added an answer on May 14, 2026 at 1:10 am

    Yes. You can pass the block to the other method by prepending the block variable with an ampersand like so:

    def foo &blk
      # now, blk is a variable bound to a block object
      bar &blk
    end
    

    The reason your are getting “class: Object” is that Ruby uses lexical scoping. This means that self in puts "class: #{self.class}" refers to main, the default context.

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