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Home/ Questions/Q 8674413
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T19:42:17+00:00 2026-06-12T19:42:17+00:00

This is working newRow.replace(‘[[‘ + key + ‘]]’, item); but i tried replacing with

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This is working

newRow.replace('[[' + key + ']]', item);

but i tried replacing with regex but its not working

newRow.replace('/\[\[' + key + '\]\]/'g, item);
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  1. Editorial Team
    Editorial Team
    2026-06-12T19:42:18+00:00Added an answer on June 12, 2026 at 7:42 pm

    You need to use the RegExp constructor to use the string literal syntax.

    newRow.replace(new RegExp('\\[\\[' + key + '\\]\\]', 'g'), item);
    

    Also note that we needed to use \\ instead of \. This is because the \ has its own meaning in string literal syntax. Therefore to get a literal \ character in the string passed to the constructor, we need to escape it.

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