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Home/ Questions/Q 8993973
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T23:18:56+00:00 2026-06-15T23:18:56+00:00

This might be a duplicate but I had little success in finding the right

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This might be a duplicate but I had little success in finding the right answer. I’m trying to achieve something like this :

var joinArrays = function(myCollectionOfArguments) {
    return array.concat(array1, array2, ..... , arrayN);
};

In which case myCollectionOfArguments will be array1, array2, ..... , arrayN. How could I achieve something like that ? I do know that if I had a callback function I cold pass as many arguments as I would like using .apply(), but in this certain case I’m a bit confused on the approach.

EDIT : So, to be more descriptive : Instead of passing just one argument, I would to be able to pass as many as I want without having to specify it when I define the function’s arguments, in my case myCollectionOfArguments, would be just one argument when defining the function, but when I want to use the function I want to be able to pass more than one argument ;

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  1. Editorial Team
    Editorial Team
    2026-06-15T23:18:58+00:00Added an answer on June 15, 2026 at 11:18 pm

    If I get your intention right, try:

    var joinArrays = function(a) {
      return a.concat.apply(a, Array.prototype.slice.call(arguments, 1));
    };
    
    var foo = joinArrays([1, 2], [3, 4], [5, 6]);
    
    console.log(foo); // => [1, 2, 3, 4, 5, 6] 
    
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