Question

This seems horrible inefficient. Can someone give me a better Ruby way.

def round_value
  x = (self.value*10).round/10.0 # rounds to two decimal places
  r = x.modulo(x.floor) # finds remainder
  f = x.floor

  self.value = case
  when r.between?(0, 0.25)
    f
  when r.between?(0.26, 0.75)
    f+0.5
  when r.between?(0.76, 0.99)
    f+1.0
  end
end

Answer 1

class Float
  def round_point5
    (self * 2).round / 2.0
  end
end

A classic problem: this means you’re doing integer rounding with a different radix. You can replace ‘2’ with any other number.