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Home/ Questions/Q 8258671
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T02:37:27+00:00 2026-06-08T02:37:27+00:00

This works: SELECT DISTINCT HEX(group_uuid) AS hexid FROM schema.table >9B3D8DE01E1E049DA9F17D42B324AA66 >CDF112D740CE14EA08CA90E3C937DE8D as does this

  • 0

This works:

SELECT DISTINCT HEX(group_uuid) AS hexid 
FROM schema.table

>9B3D8DE01E1E049DA9F17D42B324AA66
>CDF112D740CE14EA08CA90E3C937DE8D

as does this

SELECT  GROUP_CONCAT('\'', HEX(group_uuid), '\' ') AS hexid 
FROM schema.table

>'9B3D8DE01E1E049DA9F17D42B324AA66','9B3D8DE01E1E049DA9F17D42B324AA66' [etc...]

and this

SELECT  GROUP_CONCAT(DISTINCT HEX(group_uuid) SEPARATOR '\' ') AS hexid 
FROM schema.table

>9B3D8DE01E1E049DA9F17D42B324AA66' CDF112D740CE14EA08CA90E3C937DE8D

this, however,

SELECT  GROUP_CONCAT('\'', DISTINCT HEX(group_uuid), '\' ') AS hexid 
FROM schema.table 

Error Code: 1064. You have an error in your SQL syntax; INSERT COIN

does not.

Is there some kind ‘PREFIX’ keyword that can be substituted or another syntax I’m supposed to follow?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T02:37:29+00:00Added an answer on June 8, 2026 at 2:37 am

    Are you looking for

     GROUP_CONCAT(DISTINCT CONCAT('\'',HEX(group_uuid),'\'') SEPARATOR ' ')
    
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