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Home/ Questions/Q 6469945
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:03:07+00:00 2026-05-25T06:03:07+00:00

TMyBaseClass=class constructor(test:integer); end; TMyClass=class(TMyBaseClass); TClass1<T: TMyBaseClass,constructor>=class() public FItem: T; procedure Test; end; procedure TClass1<T>.Test;

  • 0
TMyBaseClass=class
  constructor(test:integer);
end;

TMyClass=class(TMyBaseClass);

TClass1<T: TMyBaseClass,constructor>=class()
  public
    FItem: T;
    procedure Test;
end;

procedure TClass1<T>.Test;
begin
  FItem:= T.Create;
end;

var u: TClass1<TMyClass>;
begin
  u:=TClass1<TMyClass>.Create();
  u.Test;
end;

How do I make it to create the class with the integer param. What is the workaround?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:03:08+00:00Added an answer on May 25, 2026 at 6:03 am

    Just typecast to the correct class:

    type
      TMyBaseClassClass = class of TMyBaseClass;
    
    procedure TClass1<T>.Test;
    begin
      FItem:= T(TMyBaseClassClass(T).Create(42));
    end;
    

    Also it’s probably a good idea to make the constructor virtual.

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