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Home/ Questions/Q 8772025
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T17:56:17+00:00 2026-06-13T17:56:17+00:00

Trying to wrap my head around this function any_name($div,$width = false){ if($width){ $add_style =’

  • 0

Trying to wrap my head around this

function any_name($div,$width = false){

   if($width){

      $add_style =' style="width:1000px;"';

   }else{
      $add_style ='';
    }

   html ='<div id="'.$div.'"'.$add_style.'>';
   html .= "</div>';

}




any_name('div1');// should print <div id="div1"></div>
any_name('div2',$width = true);// should print <div id="div2" style="width:1000px;"></div>

second function call prints

1
<div id="div2"></div>

What am I doing wrong ?

Any help is appreciated thank you!

! fund the real issue , my function has 2 more arguments
function ( $div,arg2,arg3,$width) the $width was in wrong place thus was resulting in 1

sorry for the confusion

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  1. Editorial Team
    Editorial Team
    2026-06-13T17:56:18+00:00Added an answer on June 13, 2026 at 5:56 pm
    function any_name($div, $width = false) {
    
        if ($width) {
            $add_style =' style="width:1000px;"';
        }
        else {
            $add_style ='';
        }
    
       $html ='<div id="'.$div.'"'.$add_style.'>';
       $html .= '</div>';
       return $html;
    
    }
    
    echo any_name('div1');// should print <div id="div1"></div>
    echo any_name('div2', true);// should print <div id="div2" style="width:1000px;"></div>
    
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