Question

Type()
{
    if [ -d $1 ]
        then
            return 1
    elif [ -e $1 ]
        then
            return 2
    else
            return 0
    fi
}

Types()
{
    local arg1 arg2
    for arg1 in $@
        do
            arg2=$(Type $arg1)
            if [ arg2 -eq 1 ]
                then
                    echo "$arg1 est un répertoire."
            elif [ arg2 -eq 2 ]
                then
                    echo "$arg1 n est pas un répertoire."
            else
                    echo "$arg1 ne correspond à aucune entrée du répertoire."
            fi
    done
}

I don’t know how can I use the function ‘Type’ in ‘Types’. I tried “arg2=$(Type $arg1)” bur it doesn’t seem to work. What’s the correct syntax please ?

Answer 1

If you want to use the function with $(Type ...), then you can change the return ... statements to echo ... (not exec echo ..., which does something else). If you want to keep the return ... statements in Type(), then you need to do something like Type ...; arg2=$? to test the return code from Type().