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Editorial Team
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Asked: 2026-06-11T12:25:43+00:00

typedef const char* Argv[3+ 8]; My guess at this point is the [3+8] is

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typedef const char* Argv[3+ 8];

My guess at this point is the [3+8] is creating an anonymous array of type Argv (which is of type const char*). If I’m right, the anonymous array part is basically meaningless.

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1 Answer

  1. Editorial Team

    It defines Argv as a synonym for “array of 11 const char*”.

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