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Home/ Questions/Q 6865149
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Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T03:00:18+00:00 2026-05-27T03:00:18+00:00

Used one hidden element to capture changed value and change the element value using

  • 0

Used one hidden element to capture changed value

and change the element value using jquery

changeValue(no){
   $('#mobileno').val(no);
}

and then pass the value to ajax

$.ajax({
    url:url,
    type: 'post',       
    data: '{"id":"1", "mobileno":$("#mobileno").val()}',
    success: function(data, status) {
    console.log("Success!!");        
    },    
});

mobileno field always shows empty value value while posting, if i am used alert in change value method then it is working fine

changeValue(no){
 $('#mobileno').val(no);    
 alert( $('#mobileno').val());
}

then it is working fine, your help will be appreciated

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:00:19+00:00Added an answer on May 27, 2026 at 3:00 am

    You’ve quoted your JS object making it into a string

    $.ajax({
        url:url,
        type: 'post',       
        data: '{"id":"1", "mobileno":$("#mobileno").val()}',
        ------^                                            ^--------
        success: function(data, status) {
        console.log("Success!!");        
        },    
    });
    

    Use this

    $.ajax({
        url:url,
        type: 'post',       
        data: {"id":"1", "mobileno": $("#mobileno").val() },
        success: function(data, status) {
        console.log("Success!!");        
        }    
    });
    
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