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Home/ Questions/Q 6890683
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T06:18:50+00:00 2026-05-27T06:18:50+00:00

Using Mathematica Binary String: FBCD #1 I: ImportString[FBCD, {Binary, Bit}] O: {0, 1, 0,

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Using Mathematica

Binary String: "FBCD"

#1
I: ImportString["FBCD", {"Binary", "Bit"}]
O: {0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 1, 0, \
    0, 1, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0}

#2
I: ImportString["FBCD", {"Binary", "UnsignedInteger32"}]
O: {1145258566}

#3
I: ImportString["FBCD", {"Binary", "Byte"}]
O: {70, 66, 67, 68}

What is actual math formula using the byte values {70, 66, 67, 68} in the output of #3 to get the int32 value {1145258566} in the output of #2?

(70^4)+(66^3)+(67^2)+68
I know this isn’t correct, looking for the correct formula if there is one.

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  1. Editorial Team
    Editorial Team
    2026-05-27T06:18:50+00:00Added an answer on May 27, 2026 at 6:18 am

    ( ( ( 68 * 256 ) + 67 ) * 256 + 66 ) * 256 + 70 = 1145258566

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