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Asked: May 11, 20262026-05-11T00:56:00+00:00 2026-05-11T00:56:00+00:00

Using Python 2.6, is there a way to check if all the items of

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Using Python 2.6, is there a way to check if all the items of a sequence equals a given value, in one statement?

[pseudocode] my_sequence = (2,5,7,82,35)  if all the values in (type(i) for i in my_sequence) == int:      do() 

Instead of, say:

my_sequence = (2,5,7,82,35) all_int = True for i in my_sequence:     if type(i) is not int:         all_int = False         break  if all_int:     do() 
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  1. 2026-05-11T00:56:01+00:00Added an answer on May 11, 2026 at 12:56 am

    Use:

    all( type(i) is int for i in lst ) 

    Example:

    In [1]: lst = range(10) In [2]: all( type(i) is int for i in lst ) Out[2]: True In [3]: lst.append('steve') In [4]: all( type(i) is int for i in lst ) Out[4]: False 

    [Edit]. Made cleaner as per comments.

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