Using scanf, each number typed in, i would like my program to
print out two lines: for example
byte order: little-endian
> 2
2 0x00000002
2.00 0x40000000
> -2
-2 0xFFFFFFFE
-2.00 0xC0000000
I can get it to print out the 2 in hex
but i also need a float and of course i cant scanf as one
when i need to also scan as an int
If i cast as a float when i try to printf i get a zero. If i scan in as a float
i get the correct output. I have tried to convert the int to a
float but it still comes out as zero.
here is my output so far
Int - float - hex
byte order: little-endian
>2
2 0x000002
2.00 00000000
it looks like i am converting to a float fine
why wont it print as a hex?
if i scan in as a float i get the correct hex representation like the first example.
this should be something simple. i do need to scan in as a decimal
keep in mind
i am running this in cygwin
here is what i have so far..
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
int HexNumber;
float convert;
printf("Int - float - hex\n");
int a = 0x12345678;
unsigned char *c = (unsigned char*)(&a);
if (*c == 0x78)
{
printf("\nbyte order: little-endian\n");
}
else
{
printf("\nbyte order: big-endian\n");
}
printf("\n>");
scanf("%d", &HexNumber);
printf("\n%10d ",HexNumber);
printf("%#08x",HexNumber);
convert = (float)HexNumber; // converts but prints a zero
printf("\n%10.2f ", convert);
printf("%#08x", convert); // prints zeros
return 0;
}
try this:
[EDIT]
@Corey:
let’s parse it from inside out:
the following is more concise, but it’s hard to remember the C language’s operator associativity and operator precedence(i prefer the extra clarity of some added parenthesis and whitespace provides):