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Home/ Questions/Q 7545481
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T08:56:27+00:00 2026-05-30T08:56:27+00:00

var a = function(){ this.x = function(){alert(‘apple’);} this.y = function(callback){ if(typeof callback == ‘undefined’

  • 0
var a = function(){

    this.x = function(){alert('apple');}
    this.y = function(callback){
        if(typeof callback == 'undefined' || callback == null)
            alert('argh')
        else
            callback();
    }
}
var foo = function(){alert('blah')};
var x = new a();
x.y(this.x); // why is this one undefined
x.y(foo); // works as expected

​
here is the jsfiddle link: http://jsfiddle.net/W7FyZ/2/

Why is it undefined when I pass in a object member function? Is there a way to pass a object member function as a callback?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T08:56:29+00:00Added an answer on May 30, 2026 at 8:56 am

    I have just renamed your variable to clear the confusion.

    var a = function(){
        this.x = function(){alert('apple');}
        this.y = function(callback){
            if(typeof callback == 'undefined' || callback == null)
                alert('argh')
            else
                callback();
        }
    }
    var foo = function(){alert('blah')};
    

    Now, In the execution part:

    var myA = new a();
    

    Above line is assigning function a() variable ‘myA’. So,Functions x() and y() of a(),should be called as myA.x() and myA.y().

    x.y(myA.x); // it works 
    x.y(this.myA.x) // This also works as this is a current window
    x.y(foo); // works as expected
    
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