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Home/ Questions/Q 7581635
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T18:14:44+00:00 2026-05-30T18:14:44+00:00

var Person = function(name, age){ return Object.create(Object.prototype, { name: { value: name | ,

  • 0
var Person = function(name, age){
    return Object.create(Object.prototype, {
        name: {
            value: name | "",
            writable: true,
            enumerable: true,
            configurable: true
        },
        age: {
            value: age | "",
            writable: true,
            enumerable: true,
            configurable: true
        }
    });
};

var Boy = function(name, age){
    return Object.create(Person(name, age), {
        gender: {
            value: "male"
        }
    });
};

var p = Person("John", 28);
var b = Boy();

console.log(p.isPrototypeOf(b)); // false?

I’m trying to understand object.create and how best to use it avoiding use of constructors the new keyword. So far I am approaching it as above (although probably not the best way, just trial and error) – and came across that if I use object.create I am no longer able to check instanceof and object type.

Someone suggested using isPrototypeOf to check – I’m doing something wrong as my code above returns false when checking.

Would anyone be kind enough to explain where I am going wrong? I’m still new to prototypal inheritance in javascript.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T18:14:45+00:00Added an answer on May 30, 2026 at 6:14 pm

    Of course p is not a prototype of b.

    That’s because the Person function returns a new Object each time.

    Try the following

    var Boy = function(person, name, age){
        return Object.create(person, {
            gender: {
                value: "male"
            }
        });
    };
    
    
    var p = Person("John", 28);
    var b = Boy(p);
    assert(p.isPrototypeOf(b))
    
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