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Home/ Questions/Q 7439081
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T10:39:13+00:00 2026-05-29T10:39:13+00:00

What I want to do is following. Lets say we have array like that

  • 0

What I want to do is following.

Lets say we have array like that

$arr=array();
$arr[1]['test1']="something";
$arr[1]['test2']="something else"

…

$arr[2]['test1']="blah blah";
$arr[2]['test2']="foo bar"

…

I want to echo them one by one like that

something   something else ... <all elements of $arr[1]>

blah blah  foo bar         ... <all elements of $arr[2]>

BUT!

if($arr[1]['test1']=="something")
don't echo elements of $arr[1] at all

Is that possible by new array creation in which $arr[1] doesn’t exist at all? Or during echo?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T10:39:14+00:00Added an answer on May 29, 2026 at 10:39 am

    Maybe this should do the trick:

    // Iterate and show the words
    foreach ($arr as $words) {
        if (in_array("something", $words))
            continue;
    
        echo join(' ', $words) . '<br />';
    }
    

    The continue call will jump to the next iteration, so it will skip the array if it contains the “something” element

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