Question

What is the most elegant and efficient way to convert a nested std::vector of std::vectors to cv::Mat? The nested structure is holding an array, i.e. all the inner std::vectors have the same size and represent matrix rows. I don’t mind the data being copied from one to another.

I know that a single, non-nested std::vector is very easy, there is a constructor:

std::vector <double> myvec;
cv::Mat mymat;

// fill myvec
bool copy = true;

myMat = cv::Mat(myvec, copy);

What about the nested vector?

Answer 1

This is a way to do it:

std::vector<double> row1;
row1.push_back(1.0); row1.push_back(2.0); row1.push_back(3.0);

std::vector<double> row2;
row2.push_back(4.0); row2.push_back(5.0); row2.push_back(6.0);

std::vector<std::vector<double> > vector_of_rows;
vector_of_rows.push_back(row1);
vector_of_rows.push_back(row2);

// make sure the size of of row1 and row2 are the same, else you'll have serious problems!
cv::Mat my_mat(vector_of_rows.size(), row1.size(), CV_64F);

for (size_t i = 0; i < vector_of_rows.size(); i++)
{   
    for (size_t j = 0; j < row1.size(); j++)
    {   
        my_mat.at<double>(i,j) = vector_of_rows[i][j];
    }   
}   

std::cout << my_mat << std::endl;

Outputs:

[1, 2, 3;
  4, 5, 6]

I tried another approach using the constructor of Mat and the push_back() method but without success, maybe you can figure it out. Good luck!