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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T22:37:11+00:00 2026-05-31T22:37:11+00:00

What would be the most elegant and efficient way of finding/returning the first list

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What would be the most elegant and efficient way of finding/returning the first list item that matches a certain criterion?

For example, if I have a list of objects and I would like to get the first object of those with attribute obj.val==5. I could of course use list comprehension, but that would incur O(n) and if n is large, it’s wasteful. I could also use a loop with break once the criterion was met, but I thought there could be a more pythonic/elegant solution.

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  1. Editorial Team
    Editorial Team
    2026-05-31T22:37:12+00:00Added an answer on May 31, 2026 at 10:37 pm

    If you don’t have any other indexes or sorted information for your objects, then you will have to iterate until such an object is found:

    next(obj for obj in objs if obj.val == 5)
    

    This is however faster than a complete list comprehension. Compare these two:

    [i for i in xrange(100000) if i == 1000][0]
    
    next(i for i in xrange(100000) if i == 1000)
    

    The first one needs 5.75ms, the second one 58.3µs (100 times faster because the loop 100 times shorter).

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