Question

What would be the output of this program ?

#include<stdio.h>
#include<conio.h>
void main()
{
    clrscr();
    int x=20,y=30,z=10;
    int i=x<y<z;
    printf("%d",i);
    getch();
}

Actually i=20<30<10, so the condition is false and the value of i should be 0 but i equals 1. Why?

Answer 1

This int i=x<y<z; doesn’t work the way you intended.

The effect is int i=(x<y)<z;, where x<yis evaluated first, and the value true is then compared to z.

---

Pascal points out below that in C the result of the comparison is 1 instead of true. However, the C++ true is implicitly converted to 1 in the next comparison, so the result is the same.