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Home/ Questions/Q 6822629
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T21:41:11+00:00 2026-05-26T21:41:11+00:00

When defining a member function pointer that points to a function inherited privately from

  • 0

When defining a member function pointer that points to a function inherited privately from a base class, how would you declare it?

eg..

// class B defined here

class A; //forward dec

typedef void (B::*fnc_ptr)(); // This? or..
typedef void (A::*fnc_ptr)(); // this...?

class A: private B{
   public:
      A(): ptr(0){};
      ~A(){};

      using B::fnc;

      void setandcall(){
           ptr = &fnc;
           (*ptr)();
      }

      fnc_ptr ptr;
};
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T21:41:12+00:00Added an answer on May 26, 2026 at 9:41 pm

    You have not attached the error you are getting. I think your real error might be that both

    typedef (B::*fnc_ptr)(); // This? or..
    typedef (A::*fnc_ptr)(); // this...?
    

    of your choices don’t have a return type specified.

    That being said both of your constructs will work. You problem is that when you invoke a non static member function you need to pass this parameter. The private inheritance only affects consumers of A not A itself.

    class B
    {
    public:
        void fnc();
    
    };
    
    
    typedef void (B::*fnc_ptr)(); // This? or..
    
    class A: private B{
    
    
    
       public:
          A(): ptr(0){};
          ~A(){};
    
    
          void setandcall(){
              ptr = &B::fnc;
              (this->*fnc)();
          }
    
          fnc_ptr ptr;
    };
    
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