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Home/ Questions/Q 8898549
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T00:38:23+00:00 2026-06-15T00:38:23+00:00

when I do this (in my class) public: Entity() { re_sprite_eyes = new sf::Sprite();

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when I do this (in my class)

public:
    Entity()
    {
        re_sprite_eyes = new sf::Sprite();
        re_sprite_hair = new sf::Sprite();
        re_sprite_body = new sf::Sprite();
    }

private:
    sf::Sprite* re_sprite_hair;
    sf::Sprite* re_sprite_body;
    sf::Sprite* re_sprite_eyes;

Everything works fine. However, if I change the declarations to this:

private:
    sf::Sprite* re_sprite_hair, re_sprite_body, re_sprite_eyes;

I get this compiler error:

error: no match for 'operator=' in '((Entity*)this)->Entity::re_sprite_eyes = (operator new(272u), (<statement>, ((sf::Sprite*)<anonymous>)))

And then it says candidates for re_sprite_eyes are sf::Sprite objects and/or references.

Why does this not work? Aren’t the declarations the same?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T00:38:25+00:00Added an answer on June 15, 2026 at 12:38 am

    sf::Sprite* re_sprite_hair, re_sprite_body, re_sprite_eyes;

    Does not declare 3 pointers – it is one pointer and 2 objects.

    sf::Sprite* unfortunately does not apply to all the variables declared following it, just the first. It is equivalent to

    sf::Sprite* re_sprite_hair;
    sf::Sprite re_sprite_body;
    sf::Sprite re_sprite_eyes;
    

    You want to do:

    sf::Sprite *re_sprite_hair, *re_sprite_body, *re_sprite_eyes;

    You need to put one star for each variable. In such cases I prefer to keep the star on the variable’s side, rather than the type, to make exactly this situation clear.

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