Question

When I run this code, it iterates, but then returns “The answer is 0”, when it should be “The answer is 10.”

Why is this?

#import <Foundation/Foundation.h>

int main (int argc, const char * argv[])
{
     int i;
     for (int i = 0; i < 12; i++){ 
        if (i % 3 == 0) {
            continue;
         }
         printf("Checking i = %d\n", i);
         if (i + 90 == i * i) {
             break;
         }
     }
    printf("The answer is %d.\n", i);
    return 0;


}

Answer 1

You have two separate is in your code, the inner one hiding the outer one. Moreover, the print statement causes undefined behaviour, because the outer i is read uninitialized.

Say for (i = 0; i < 12; i++) to use the outer variable instead of declaring a new variable.