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Home/ Questions/Q 6672297
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T03:29:30+00:00 2026-05-26T03:29:30+00:00

When print_array is called, the size of the int array[] parameter (count) isn’t what

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When print_array is called, the size of the int array[] parameter (count) isn’t what was expected. It seems sizeof is not returning the size of the entire array which would be 5*sizeof(int) = 20.

namespace Util
{
   void print_array(int array[])
   {
      size_t count = (sizeof array)/(sizeof array[0]);
      cout << count;
      // int count = sizeof(array)/sizeof(array[0]);
      // for (int i = 0; i <= count; i++) cout << array[i];
   }
}


int array_test[5]={2,1,5,4,3};
Util::print_array(array_test);
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  1. Editorial Team
    Editorial Team
    2026-05-26T03:29:30+00:00Added an answer on May 26, 2026 at 3:29 am

    int array[] here becomes int* array, and sizeof(array) returns the same thing sizeof(int*). You need to pass an array by reference to avoid that.

    template <size_t N>
    void print_array(int (&array)[N]) {
        std::cout << N;
    }
    
    int array[] = { 2, 1, 5, 4, 3 };
    print_array(array);
    
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