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Home/ Questions/Q 8108293
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T01:04:05+00:00 2026-06-06T01:04:05+00:00

While looking into parallel programming, and subsequently evaluation strategies, the question whether thunks are

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While looking into parallel programming, and subsequently evaluation strategies, the question whether thunks are mutable came up. To give an example, let’s say I have the following code:

foo = 1 + 2         -- Thunk
bar = foo `seq` foo -- Evaluates foo

Calling seq when evaluating bar evaluates foo, giving bar the normal form value 3. Does this evaluation affect foo as well? That is, is the value of foo still 1+2 or is it 3 after evaluating bar?

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  1. Editorial Team
    Editorial Team
    2026-06-06T01:04:06+00:00Added an answer on June 6, 2026 at 1:04 am

    The Haskell report only specifies that the evaluation order is “non-strict”, so either behavior would conform to the standard.

    However, using lazy (“call by need”) evaluation, which involves sharing values in a way that makes thunks “mutable” as you describe, offers asymptotic improvements over “call by name” (that is, no sharing).

    So in GHC (and probably most other reasonable implementations), foo will become 3 after you force it for the first time. However, this is not mandated by the standard, which you should keep in mind.

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