Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 504223
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T06:28:29+00:00 2026-05-13T06:28:29+00:00

While trying to make a regular constructor to constructor call in the same class

  • 0

While trying to make a regular constructor to constructor call in the same class :

    public Equation(OrdinaryEquations equation, 
                    double xTranslation,
                    double yTranslation, 
                    double rotationAngle)
      : this( (equation == OrdinaryEquations.SecondOrder) ? new EquationFunction(SecondOrderEquation) : new EquationFunction(ThirdOrderEquation), 
        xTranslation, yTranslation, rotationAngle){}

OrdinaryEquations is enumeration

EquationFunction is a delegate

I get this error :
” An object reference is required for the non-static field, method, or property”
foreach : ” new EquationFunction(SecondOrderEquation)” and “new EquationFunction(ThirdOrderEquation)”
which sounds like when I try to access object data from static method

the other constructor sig. :

public Equation(EquationFunction equation, double xTranslation, double yTranslation, double rotationAngle){}

Is there something I’m missing here ? I can’t figure out what to do !!

P.S I removed the conditional operator and made it a normal object initialization but gave the same error

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T06:28:29+00:00Added an answer on May 13, 2026 at 6:28 am

    I assume “SecondOrderEquation” is a method name in your class “Equation”.
    The usage of “SecondOrderEquation” refers to this.SecondOrderEquation which needs a instance of type “Equation” to be a context.

    To fix it, you can try to make “SecondOrderEquation” and “ThirdOrderEquation” to be static methods.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 452k
  • Answers 452k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer Yes, you can... May 15, 2026 at 9:05 pm
  • Editorial Team
    Editorial Team added an answer Nevermind, I found the solution. You can read it here:… May 15, 2026 at 9:05 pm
  • Editorial Team
    Editorial Team added an answer Look at the definitions for RTP and RTCP packets in… May 15, 2026 at 9:05 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.