Question

Why does str(A()) seemingly call A.__repr__() and not dict.__str__() in the example below?

class A(dict):     def __repr__(self):         return 'repr(A)'     def __str__(self):         return dict.__str__(self)  class B(dict):     def __str__(self):         return dict.__str__(self)  print 'call: repr(A)  expect: repr(A)  get:', repr(A())   # works print 'call: str(A)   expect: {}       get:', str(A())    # does not work print 'call: str(B)   expect: {}       get:', str(B())    # works 

Output:

call: repr(A)  expect: repr(A)  get: repr(A) call: str(A)   expect: {}       get: repr(A) call: str(B)   expect: {}       get: {} 

Answer 1

str(A()) does call __str__, in turn calling dict.__str__().

It is dict.__str__() that returns the value repr(A).