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Home/ Questions/Q 8584141
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T21:42:10+00:00 2026-06-11T21:42:10+00:00

Why does the following code not throw an error? if false x = 0

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Why does the following code not throw an error?

if false
  x = 0
end

x  #=> nil

Whereas the following does throw an error:

y  # NameError: undefined local variable or method `y' for main:Object

The same thing happens with unless & case statements.

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  1. Editorial Team
    Editorial Team
    2026-06-11T21:42:12+00:00Added an answer on June 11, 2026 at 9:42 pm

    It’s because of how the Ruby parser works. Variables are defined by the parser, which walks through the code line-by-line, regardless of whether it will actually be executed.

    Once the parser sees x =, it defines the local variable x (with value nil) henceforth in the current scope. Since if/unless/case/for/while do not create a new scope, x is defined and available outside the code block. And since the inner block is never evaluated as the conditional is false, x is not assigned to (and is thus nil).

    Here’s a similar example:

    defined?(x) and x = 0
    x  #=> nil
    

    Note that this is a rather high-level overview of what happens, and isn’t necessarily exactly how the parser works.

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