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Home/ Questions/Q 7894203
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T07:20:05+00:00 2026-06-03T07:20:05+00:00

Why doesn’t this: def subsets(x): if not x: return [[]] else: return [x +

  • 0

Why doesn’t this:

def subsets(x):
    if not x:
        return [[]]
    else:
        return [x + y for x in [[], [x[0]]] for y in subsets(x[1:])]

print subsets(['a', 'b'])

produce the same output as this:

def subsets(x):
    if not x:
        return [[]]
    else:
        z = subsets(x[1:])
        return [x + y for x in [[], [x[0]]] for y in z]

print subsets(['a', 'b'])
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T07:20:06+00:00Added an answer on June 3, 2026 at 7:20 am

    The problem is that you are using the name x for two different things. When you introduce x as a variable inside a list comprehension it hides the x that was defined in the function. As a result, the final x in your list comprehension isn’t refering to the x that you had hoped for.

    Renaming one of the x to something else fixes the problem:

    def subsets(original_x):
        if not original_x:
            return [[]]
        else:
            return [x + y for x in [[], [original_x[0]]]
                          for y in subsets(original_x[1:])]
    

    I would also suggest that you try to find more descriptive names for your variables. This will reduce the likelihood of accidentally reusing a name.

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