why is Math.floor(Double.MIN_VALUE) == 0 ?
can any one send me the java algorithme of Floor function or at least explain this result please?
why is Math.floor(Double.MIN_VALUE) == 0 ? can any one send me the java algorithme
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why is Math.floor(Double.MIN_VALUE) == 0 ?
can any one send me the java algorithme of Floor function or at least explain this result please?
Double.MIN_VALUEdoesn’t mean what you think it means. It means “the smallest positivedoublevalue” – so naturally when you take the “floor” of it (largest integer less than or equal to the value), you’ll get 0. Documentation:I agree that the name is confusing, but it’s always worth checking the documentation as soon as you see confusing behaviour.
If you want to get the “lowest” finite
double, just use-double.MAX_VALUE.