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Home/ Questions/Q 6336091
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T18:58:57+00:00 2026-05-24T18:58:57+00:00

Why is PRINT THIS in the code below never printing? I’ve already cout <<

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Why is PRINT THIS in the code below never printing? I’ve already cout << shiftx and shifty to make sure that at some point, they both are 0.3.

for(double shifty=0; shifty < 2; shifty+=.1) {
    for(double shiftx=0; shiftx < 2; shiftx +=.1) {
        if((shiftx == 0.3) && (shifty == 0.3)) {
            cout << "PRINT THIS" << endl;
        }
    }    
}
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  1. Editorial Team
    Editorial Team
    2026-05-24T18:58:58+00:00Added an answer on May 24, 2026 at 6:58 pm

    The golden rule is: avoid equality tests in floating-point.

    Neither 0.1 nor 0.3 can be exactly represented.

    Standard reading: What Every Computer Scientist Should Know About Floating-Point Arithmetic.

    To solve your particular problem, you should iterate and perform comparisons using integer types. Only convert to floating-point types when you actually need to. e.g.:

    for(int shifty=0; shifty < 20; shifty++) {
        for(int shiftx=0; shiftx < 20; shiftx++) {
            double shifty_double = shifty * 0.1;
            double shiftx_double = shiftx * 0.1;
            if((shiftx == 3) && (shifty == 3)) {
                cout << "PRINT THIS" << endl;
            }
        }    
    }
    
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