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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T01:24:50+00:00 2026-05-28T01:24:50+00:00

According to cppreference.com, the C++ static_cast operator’s level of precedence is 2 . Why

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According to cppreference.com, the C++ static_cast operator’s level of precedence is 2.

Why are those levels even defined? I can’t think of any reason. Can anyone provide an example?

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  1. Editorial Team
    Editorial Team
    2026-05-28T01:24:51+00:00Added an answer on May 28, 2026 at 1:24 am

    The standard doesn’t define precedence levels; these can be derived from the grammar.

    Like any other syntactical feature, static_cast has a place in this grammar. Because its use requires parentheses its operand expression can never be ambiguous, but that only means that it makes no sense to bother deriving a precedence level for it from the grammar, not that its place in the grammar itself is meaningless. Thus the standard is doing nothing crazy here.

    What’s pointless is that whatever source you cited listed a precedence level for static_cast. It’s not wrong, it’s just pointless.

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