Question

Got a seg fault from my memcpy that gdb can’t give me anything else on (at least beyond the simple manner that I know how to use gdb…). This thing is deeply imbedded in some code using the Berkely DB; I have taken out the only lines that should be of any use.

  void *databuf;
  int smallest;
  databuf=malloc(2*sizeof(int));
  memset(databuf,0,2*sizeof(int));



  /* This next line comes from the DB structures; key.data is a void*... */
  smallest=*(int *)key.data;

  memcpy(databuf,(void *)smallest,sizeof(int));

To confirm the variable smallest is correct, I can run gdb and get

(gdb) print smallest
$1 = 120321

The error I recieve (in gdb) is the useless

Program received signal SIGSEGV, Segmentation fault.
0x08048efa in main (argc=4, argv=0xbffff344) at index_DB-1.1.c:128
128       memcpy(databuf,(void *)smallest,sizeof(int));
(gdb) backtrace
#0  0x08048efa in main (argc=4, argv=0xbffff344) at index_DB-1.1.c:128

The reason I am doing this is mostly because I am bastardizing the Berkley DB tutorial, but also later I want to do

memcpy(databuf+len,(void *)largest,sizeof(int));

i.e. have a void pointer databuf with first byes the smallest integer and second bytes the largest integer. What am I missing?

Answer 1

In this step, you are interpreting the value in smallest as a pointer:

memcpy(databuf,(void *)smallest,sizeof(int));

Since that value is almost certainly not a valid pointer, this is causing your segfault. Instead, you likely want:

memcpy(databuf, &smallest, sizeof smallest);

Unless you need smallest for some other reason though, you can just copy directly from key.data to to databuf:

memcpy(databuf, key.data, sizeof(int));