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Home/ Questions/Q 6219327
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T07:45:34+00:00 2026-05-24T07:45:34+00:00

I don’t get why this.array[0] equals 1 if this.array[0] = [(2,1)] ? What does

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I don’t get why this.array[0] equals 1 if this.array[0] = [(2,1)]?
What does Javascript do with the 2 and how do i reach/use it? How does parenthesis work inside arrays?

I’d like to do different things with X if the boolean before it is true or false.
this.array[0] = [(true, X)] and this.array[0] = [(false, X)].

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  1. Editorial Team
    Editorial Team
    2026-05-24T07:45:35+00:00Added an answer on May 24, 2026 at 7:45 am

    Parenthesis in that context act as a statement with the last item passed being the passed value.

    In other words:

    (2, 1) === 1
    

    The 2 is evaluated, however, so:

    (foo(), bar())
    

    is effectively doing:

    foo();
    return bar();
    

    What you want in this case is [2, 1]

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