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Home/ Questions/Q 6477447
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:56:57+00:00 2026-05-25T06:56:57+00:00

I have a 3d array defined like so: val 3dArray = new Array[Array[Array[Int]]](512, 8,

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I have a 3d array defined like so:

val 3dArray = new Array[Array[Array[Int]]](512, 8, 8)

In Javascript I would do the following to assign each element to 1:

for (i = 0; i < 512; i++)
 {
    3dArray[i] = [];
    for (j = 0; j < 8; j++)
    {
        3dArray[i][j] = [];
        for (k = 0; k < 8; k++)
        {
            3dArray[i][j][k] = 1;
        }
    }
}

What’s the most elegant approach to doing the same?

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:56:57+00:00Added an answer on May 25, 2026 at 6:56 am

    Not sure there’s a particularly elegant way to do it, but here’s one way (I use suffix s to indicate dimension, i.e. xss is a two-dimensional array).

    val xsss = Array.ofDim[Int](512, 8, 8)
    for (xss <- xsss; xs <- xss; i <- 0 until 8) 
      xs(i) = 1
    

    Or, using transform it gets even shorter:

    for (xss <- xsss; xs <- xss)
      xs transform (_ => 1)
    
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