Question

I have a class called Person:

class Person {
    string name;
    long score;
public:
    Person(string name="", long score=0);
    void setName(string name);
    void setScore(long score);
    string getName();
    long getScore();
};

In another class, I have this method:

void print() const {
     for (int i=0; i< nPlayers; i++)
        cout << "#" << i << ": " << people[i].getScore()//people is an array of person objects
    << " " << people[i].getName() << endl;
}

This is the declaration of people:

    static const int size=8; 
    Person people[size]; 

When I try to compile it I get this error:

IntelliSense: the object has type qualifiers that are not compatible with the member function

with red lines under the the 2 people[i] in the print method

What am I doing wrong?

Answer 1

getName is not const, getScore is not const, but print is. Make the first two const like print. You cannot call a non-const method with a const object. Since your Person objects are direct members of your other class and since you are in a const method they are considered const.

In general you should consider every method you write and declare it const if that’s what it is. Simple getters like getScore and getName should always be const.