Question

I have a query something like this,

SELECT SOME_ID, COUNT(ANOTHER_ID) AS WITHOUT_FILTER 
from SOME_TABLE GROUP BY SOME_ID

this returns me

+------------+------------------+
| SOME_ID    | WITHOUT_FILTER   |
+------------+------------------+
|  1         | 40               |
|  2         | 30               |
+------------+------------------+

I have the same query with a condition which gives me filtered values.

SELECT SOME_ID, COUNT(ANOTHER_ID) AS WITH_FILTER 
from SOME_TABLE WHERE SOME_COL > 10 GROUP BY SOME_ID

which returns obviously lesser values in the grouped_by section

+------------+----------------+
| SOME_ID    | WITH_FILTER    |
+------------+----------------+
|  1         | 20             |
|  2         | 15             |
+------------+----------------+

Now, I need a query to give me both the count values ie with condition and without condition in one single query. The result should be like this

+----------+----------------+---------------+
| SOME_ID  | WITHOUT_FILTER | WITH_FILTER   |
+----------+----------------+---------------+
|  1       | 40             | 20            |
|  2       | 30             | 15            |
+------------+--------------+---------------+

Please help me.

Answer 1

You can do this:

SELECT 
    SOME_ID, 
    COUNT(ANOTHER_ID) AS WITHOUT_FILTER
    SUM(case when SOME_CONDITION then 1 else 0 end) AS WITH_FILTER

from SOME_TABLE GROUP BY SOME_ID